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This week, we return to the direct mate threemover, in which field no name stands
higher than Lev Loshinsky. The profusion of black rooks and bishops soon tells the
experienced solver that we are talking Grimshaw/Novotny!
I sourced this problem from the classic book, “Chess Problems: Introduction to an
Art”, and the commentary below is based very heavily on Robin Matthews', in that
The key is 1.Qe7! (threat 2.Be3), after which it is worth studying the
situation for a moment. At present, the Ra3 guards against two mates (Qe3 and Nh3),
but the Bb1 is not guarding against any, so there is no immediate Novotny possible
on d3. But the Bb1 does share a guard with the Ra4 against Qe4, which means that
after the interferences Bd4/Rd4, the Bb1 is left as the sole guard against Qe4 or
Qf6 respectively. This sets up the possibility of a Novotny on d3. Likewise, after
1...Nc2, only single control is left against the mates on e4 and f6, allowing
another Novotny, this time on d4. Finally, we have a couple of by-play variations
after 1...Be5 and 1...Be4, both of which self-block a BK flight.