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This week, we have a relatively rare type of problem, a reflexmate. This is a form
of selfmate, in that White is trying to force a reluctant Black to mate him.
However, in a reflexmate, either side MUST give mate in one, if it able to do so.
Thus, White only has to give Black the possibility of mate in one, in order to
solve the problem, but conversely, Black can defend by giving White the chance to
mate him in one.
If you want a clue, read on: you will perhaps observe that if the wQ were not on
the a-file, then by 1.0-0-0, White would immediately force Black to mate by
The key is 1.Qh8! Threat 2.0–0–0 a1(Q), and now all Black’s defences, which
prevent White castling, lead to his being forced to mate:
The only remaining question is why h8 is the only square for the wQ. The answer is
that each other square along the eighth rank results in White being forced to mate
Black: 1.Qb8? Kxe4 2.Qxf4#; 1.Qc8? Bxe4 2.Qc3#; 1.Qd8? Ne5 2.Qxd5#; 1.Qe8? Nc5
2.c3#; 1.Qf8? Re5 2.Qb4#; 1.Qg8? f5 2.Qxd5#
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