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A characteristic Giegold puzzler, deliberately containing what many
composers might regard as a constructional flaw.
Solution: 1.Rd2 c6 2.Kf2 Kxf4 3.Se6. With four pieces
bearing down on f4 it looks an unlikely square for the black king
to reach, but two self-interferences do the trick. The rook at f1
is there to provide the second self-interference, but its presence
is superfluous from the point of view of soundness, as the white
king must go to f2 anyway to guard the squares on the third rank.
If the f1 rook replaced the queen the pawns at a6 and c4 could be
removed while the solution remained the same.
Any comments or questions on this problem should be addressed to
Michael McDowell using the ‘Contact’ item in the menu on the left.