17th August 2020

Selected by Michael McDowell

Bill Whyatt

The Australian Problemist, 1963

4k2r/1pp2p1s/8/2Q4s/7b/1B2p3/8/3R4

Mate in 2, after replacing the white king

Something a little different this week. The white king must first be placed on the board before the problem is solved as a conventional mate in two. Which is the correct square for the king?